解：延长CD交PB于F，则DF⊥PB．∴在直角△DFB中，DF=BD?sin15°≈50×0.26=13.0mCE=BF=BD?cos15°≈50×0.97=48.5m∴AE=CE?tan10°≈48.5×0.18=8.73m．∴AB=AE+CD+DF=8.73+1.5+13=23.2m．答：树高约为23.2米．
