5x²-1=4x
5x²-4x-1=0
(x-1)(5x+1)=0
x-1=0或5x+1=0
x=1或x=-1/5
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原式=5x的平方-1-4x=0
则x=[4+/-根号下(16-4x5x-1)]/[2x5] 解得x1=1 x2=-(1/5)
5x^2-1=4x
5x^2-4x-1=0
(5x+1)(x-1)=0
x=-1/5或1
answer:
5x²-1=4x
5x²-4x-1=0
(5x+1)(x-1)=0
∴ 5x+1=0 x-1=0
x=-1/5 x=1