已知x,y为正整数,并且xy+x+y=71,x 2 y+xy 2 =880,求3x 2 +8xy+3y 2 的值.

2025-06-27 10:39:26
推荐回答(1个)
回答1:

∵xy+x+y=71
∴xy=71-(x+y)
∵x 2 y+xy 2 =880
∴x 2 y+xy 2 =xy(x+y)=[71-(x+y)]*(x+y)=71(x+y)-(x+y) 2 =880
∴(x+y) 2 -71(x+y)+880=0
∴[(x+y)-55]•[(x+y)-16]=0
∴(x+y)-55=0或(x+y)-16=0
解得:x+y=55或x+y=16
(1)当x+y=55时,代入xy+x+y=71中得:xy=16
(2)当x+y=16时,代入xy+x+y=71中得:xy=55
因为x,y为正整数,所以结果(1)不可能,去掉
3x 2 +8xy+3y 2 =3(x+y) 2 +2xy
=3×16 2 +2×55
=3×256+110
=878