(lg根号2+lg3-lg根号10)÷lg1.8

2025-06-25 05:36:50
推荐回答(1个)
回答1:

lg2^(1/2)+lg3l+g10^(1/2)=(1/2)lg2+lg3+(1/2)lg10=(1/2)[lg2++2lg3+lg10]=(1/2)lg[2(3^2)/10)=(1/2))lg(2x9/10)=(1/2)lg(18/10)=(1/2)lg1.8.原式=(1/2)(lg1.8)/(lg1.8)=1/2.