化简(x+1⼀x-1 ) – ((x的平方-2x) ⼀ x的平方-1)除以(x的平方-x-2)⼀(x的平方+2x+1)的结果是?

2025-06-24 17:55:02
推荐回答(1个)
回答1:

(x+1)/(x-1)-(x-2x)/(x-1)÷[(x-x-2)/(x+2x+1)] =(x+1)/(x-1)-x(x-2)/(x-1)÷[(x-2)(x+1)/(x+1)] =(x+1)/(x-1)-x(x-2)/[(x+1)(x-1)]÷[(x-2)/(x+1)] =(x+1)/(x-1)-x/(x-1) =1/(x-1)