函数求导.y=arctan(x+1)⼀(x-1)

2025-06-26 08:31:25
推荐回答(1个)
回答1:

y=arctan(x+1)/(x-1)
y'=1/[1+(x+1)^2/(x-1)^2]*[(x+1)/(x-1)]'
=1/[1+(x+1)^2/(x-1)^2]*[(x-1)-(x+1)]/(x-1)^2
=-2/[(x+1)^2+(x-1)^2]
=-1/(x^2+1)