D为y=0,x=1,y=x^2围成的曲边△。∫(0,1)xdx∫(0,x^2)cosydy=∫(0,1)xsiny|(0,x^2)dx=(1/2)∫(0,1)sinx^2dx^2=-(1/2)cosx^2|(0,1)=(1/2)(1-cos1)
我可以跟你讲
