化为：x^3-5x�0�5+4x-(4x-4)=0
即：x(x-1)(x-4)-4(x-1)=0
(x-1)(x�0�5-4x-4)=0
解得：x=1；x=2±2√2
x1=1；x2=2+2√2；x3=2-2√2
x^3-5x^2+4=0x^3-x^2-4x^2+4x-4x+4=0x^2(x-1)-4x(x-1)-4(x-1)=0(x-1)(x^2-4x-4)=0x-1=0或x^2-4x-4=0x1=1，x2=2+2√2，x3=2-2√2
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