已知等差数列{an }的前n项和为Sn,a8=8, S9=18,则数列a4=?

2025-06-26 13:21:51
推荐回答(3个)
回答1:

S9=9a5=18,a5=2,a8=8,求出d=(8-2)/3=2,所以a4=a5-d=2-2=0

回答2:


回答3:

a8=a1+7d=8 (1)
s9=(a1+a1+8d)X9/2=18
a1+4d=2 (2)
(1)-(2),得到:3d=6
d=2 a1=-6
a4=a1+3d=-6+3X2=0