已知sin(π⼀2+A)=3⼀7,则cos눀(π⼀2-A)为什么等于40⼀49

2025-06-23 22:13:15
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回答1:

解:
sin(π/2+A)=3/7
sin(π/2)cosA+cos(π/2)sinA=3/7
cosA=3/7
cos²(π/2-A)
=[cos(π/2)cosA+sin(π/2)sinA]²
=sin²A
=1-cos²A
=1-(3/7)²
=1-9/49
=40/49