化简求值:(1)-(x2+y2)+[-3xy-(x2-y2)],其中 x=-1,y=2.(2)已知A=3b2-2a2,B=ab-2b2-a2.求A-2

2025-06-26 07:59:27
推荐回答(1个)
回答1:

(1)原式=-x2-y2-3xy-x2+y2=-2x2-3xy,
当x=-1,y=2时,原式=-2×(-1)2-3×(-1)×2=4

(2)A-2B=3b2-2a2-2(ab-2b2-a2)=7b2-2ab,
把a=2,b=-

1
2
代入,原式=7×(-
1
2
2-2×2×(-
1
2
)=
15
4