a(n+1)=2an/(an+2),a1=2,说明an>0∵a(n+1)=2an/(an+2),∴1/a(n+1)=(an+2)/2an=1/an+1/2∴1/a(n+1)-1/an=1/2,a1=2所以｛1/an｝为等差数列
