a(x-1)2+b(x-1)+c=0a(x²-2x+1)+bx-b+c=0ax²-2ax+a+bx-b+c=0ax²-(2a-b)x+(a-b+c)=0对号入座a=12a-b=3a-b+c=-1得a=1,b=-1,c=-3所以a:b:c=1:(-1):(-3)
ax^2+(b-2a)x+a-b+c=0 与x^2-3x-1=0比较a=1b-2a=-3a-b+c=-1得出a=1 b=-1 c=-3a:b:c=1:-1:-3