原式=(2√2)²+2×2√2×3√3+(3√3)²=8+12√6+27=35+12√6
35+12倍根号6
(2√2+3√3)²=8+27+12√6=35+12√6
(2√2+3√3)²=(2√2)²+2x2√2x3√3+(3√3)²=8+12√6+27=35+12√6
35+12根号6
