解：原式=2(a-b)^2·[1/4(b-a)^6] = 2(a-b)^2·[1/4(b-a)^6] = 2(a-b)^2·[1/4(a-b)^6] =1/2(a-b)^8
2(a-b)²·[1/2（b-a）³]²= 2(a-b)^2·[1/4(b-a)^6]= 2(a-b)^2·[1/4(a-b)^6]=1/2(a-b)^8
