求助大一高数题

1） -1 <= (x-1)/3 <= 1, 解得 -2 <= x <= 4
2) 由已知2^x = y/(1-y), 即x = log2(y/1-y), 即反函数为y = log2(x/1-x), x∈(0, 1)

解1 (x-1)/3的取值范围是[-1,1],故x的范围[-2,4]
2 2^x = y/(1-y), 即x = log2(y/1-y), 即反函数为y = log2(x/1-x), x∈(0, 1)

(1)-1≤(x-1)/3≤1,
-3≤x-1≤3
-2≤x≤4
(2)y+2^x y=2^x
2^x=y/(1-y)
x=log(2)(y/(1-y))
反函数y=log(2)(x/(1-x))
定义域 0

1解：-1<=（x-1）/3<=1
求得：-2<=x<=4
2解：1/y=(1+2^x)/(2^x)
1/y=1/(2^x) + 1
1/y - 1=1/(2^x)
y/(1-y)=2^x
x=log(2)(y/(1-y))

-2