1⼀x-1-1⼀x+1-2⼀xxx+1-4⼀xxxxxxx-1-8⼀x8+1

1/x-1-1/x+1-2/xxx+1-4/xxxxxxx-1-8/x8+1
2025-06-27 18:53:05
推荐回答(1个)
回答1:

1/x-1-1/x+1-2/x²+1-4/x^4+1-8/x^8+1

=(x+1-x+1)/(x²-1)-2/(x²+1)-4/(x^4+1)-8/(x^8+1)
=2/(x²-1)-2/(x²+1)-4/(x^4+1)-8/(x^8+1)
=(2x²+2-2x²+2)/(x^4-1)-4/(x^4+1)-8/(x^8+1)
=4/(x^4-1)-4/(x^4+1)-8/(x^8+1)
=8/(x^8-1)-8/(x^8+1)
=16/(x^16-1)