由A∩B={-2}可知x=-2为x2-px-2=0和x2+qx+r=0的解,代入x2-px-2=0,求得p=-1,4-2q+r=0①.把p=-1代入到x2-px-2=0中解得x=-2,x=1.又因为A∪B={-2,1,7},可知7为x2+qx+r=0的解,代入得49+7q+r=0②;将①②联立求得q=-5,r=-14,p,q,r的值为:-1,-5,-14.
