已知tanα=3,求tan(α+π⼀4)的值

2025-06-28 21:28:19
推荐回答(1个)
回答1:

解:
tan(a+π/4)
=[tana+tan(π/4)]/[1-tana·tan(π/4)]
=(3+1)/(1-3×1)
=-2