求 d⼀dx(x∫xcost²dt)下限x²上限0

2025-06-24 02:31:29
推荐回答(1个)
回答1:

d/dx ∫cos(t²)dt
=d/dx -∫<0,x²>cos(t²)dt
=-cos[(x²)²]·(x²)'
=-2xcos(x^4)