limx→0 (tanx-sinx)⼀x求极限

2025-06-26 13:24:01
推荐回答(1个)
回答1:

lim(x→0 )(tanx-sinx)/x (这是0/0型,运用洛必达法则)
=lim(x→0 )(sec^2x-cosx)
=0