设复数z=a+bi(a、b∈R),代入已知的等式得ia+bi-1=3,i(a-1-bi)(a-1+bi)(a-1-bi)=3,b+(a-1)i(a-1)2+b2=3,∴a=1,b=13,∴a+b=1+13=43,故答案为:43.