解答一下如图行列式的解法,最好有图片解答

2025-06-26 06:18:49
推荐回答(1个)
回答1:

从第一行开始, 每一行减下一行
0 1 1 1 ... 1 1
0 1-x 1 1 ... 1 1
0 0 1-x 1 ... 1 1
0 0 0 1-x... 1 1
......
0 0 0 0 ... 1-x 1
1 x x x ... x 1

按第1列展开得
D = (-1)^(n+1)*
1 1 1 ... 1 1
1-x 1 1 ... 1 1
0 1-x 1 ... 1 1
0 0 1-x... 1 1
...
0 0 0 ...1-x 1

第1行乘 -1 加到其余各行
1 1 1 ... 1 1
-x 0 0 ... 0 0
-1 -x 0 ... 0 0
-1 -1 -x... 0 0
...
-1 -1 -1 ...-x 0

按最后一列展开
D = (-1)^(n+1)*(-1)^(1+n-1) * (-x)^(n-2)
= (-1)^(n-1) x^(n-2).