log1/3 36=-log3(3^2*4)=-(2+log3(4) )又4>2+log3(4)>3,故0<2+log3(4)-3<1偶函数得:f(log1/3 (36))=f[-(2+log3(4)]=f(2+log3(4))f(x)=f(x+3)得:f(2+log3(4))=f[2+log3(4)-3]=f(log3(4)-1)=3^(log3(4)-1)=3^log3(4)/3=4/3即原式=4/3
